www.argio-logic.net

Hi,
I would like to post instructions on how to solve yesterdays frame sudoku. Which format to use to upload pics? When I change the definition in MS Paint to 300x300 pixels the picture gets too blurry.

You can save pictures in a public storage service like Dropbox, then post the Url with the "Img" button.

Frame sudoku from 12 maggio 2015, Tiramisu contra Buseca epic pareggio from Torneo de Aglioni. As our teammate couldnt solve the puzzle which led to a pareggio, I decided to make instructions on how to solve this puzzle.

Row 9 – sum 23 must be 689, sum 7 in the middle (45-15-23=7) 124
Row 5 – sum 7 in the middle 124
Column 5 – sum 9 in the middle 135

my pics dont work

could someone tell me if this link works? thanks

https://www.dropbox.com/s/g2dlb5sw2rctjpl/frame1.jpg?dl=0

jzverina ha scritto:could someone tell me if this link works? thanks

https://www.dropbox.com/s/g2dlb5sw2rctjpl/frame1.jpg?dl=0

Yes, the link works, but the tag [img] does'nt downolad from https.
I have increased the size (up to 100 kb) and the pixels (up to 900x900) of each attached image.
Try now attaching your images.

jzverina ha scritto:could someone tell me if this link works? thanks

https://www.dropbox.com/s/g2dlb5sw2rctjpl/frame1.jpg?dl=0

Yes, it works. But, i don't know why, If i put this link between the (Img) instead of (url) it does'nt work.

jzverina ha scritto:Frame sudoku from 12 maggio 2015, Tiramisu contra Buseca epic pareggio from Torneo de Aglioni. As our teammate couldnt solve the puzzle which led to a pareggio, I decided to make instructions on how to solve this puzzle.

Row 9 – sum 23 must be 689, sum 7 in the middle (45-15-23=7) 124
Row 5 – sum 7 in the middle 124
Column 5 – sum 9 in the middle 135

frame1.jpg

Hi Jzverina. I also started as you ....

Column 6 – sum 10 cant contain 7 or higher, it will be either 136 or 235
Column 4 – sum 12 must therefore contain 3

Row 8 – sum 14 cant contain 6, it would be impossible to make the rest 8 (17, 26, 35)
Therefore 6 in row 8 is located in the middle. The rest is 14 (45-14-11-6) which must be 59

Column 5 – sum 19 can contain neither 1 nor 4, hence r9c5=2

Row 6 – sum of the middle is 20, it cant contain 5 as both combinations for 15 (78, 69) are blocked

Rows 456 – there are many ways to allocate digits into triplets
Row 4 – sum 11 cant contain 9, hence 9 in box 6 is a part of sum 19 (19, 28, 46 are blocked, hence 937)
Row 6 – sum 10 cant contain 6 (the only combination 13 is blocked) therefore 6 in box 4 is a part of sum 19 (49 and 67 blocked, hence 658)

Column 1 – sum 15 can contain neither 1 or 9, hence r7c1=6

Column 1 – sum of the middle is 18, it cant contain 5 therefore r5c1=8

Box 1 – if 6 was a part of sum 20, the only combination for that triplet would be 569 which would be in conflict with r5c3

Column 2 – sum 13 must be 634 (16 and 25 are blocked)

Row 2 – sum 21 can contain neither 1 nor 2, hence r2c1=9

Row 2 – sum of the middle is 10, it cant contain 6 as combination 13 is blocked

Row 3 – sum of the middle is 19, it cant contain 3

Box 3 – sums 16 and 17 (columns) cant contain 1

Column 8 – sum 16 cant contain 1